ApplId/ProductId | Drug name | Active ingredient | Form | Strenght |
---|---|---|---|---|

016080/001 | MANNITOL 5% | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

016269/001 | MANNITOL 5% | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

ApplId/ProductId | Drug name | Active ingredient | Form | Strenght |
---|---|---|---|---|

005620/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

013684/001 | OSMITROL 5% IN WATER | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

013684/002 | OSMITROL 10% IN WATER | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

013684/003 | OSMITROL 20% IN WATER | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

013684/004 | OSMITROL 15% IN WATER | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

013684/005 | OSMITROL 5% IN WATER IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

013684/006 | OSMITROL 10% IN WATER IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

013684/007 | OSMITROL 20% IN WATER IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

013684/008 | OSMITROL 15% IN WATER IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

014738/001 | MANNITOL 20% | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

016080/001 | MANNITOL 5% | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

016080/002 | MANNITOL 10% | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

016080/003 | MANNITOL 15% | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

016080/004 | MANNITOL 20% | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

016080/005 | MANNITOL 15% W/ DEXTROSE 5% IN SODIUM CHLORIDE 0.45% | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

016080/006 | MANNITOL 10% W/ DEXTROSE 5% IN DISTILLED WATER | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

016080/007 | MANNITOL 5% W/ DEXTROSE 5% IN SODIUM CHLORIDE 0.12% | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

016269/001 | MANNITOL 5% | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

016269/002 | MANNITOL 10% | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

016269/003 | MANNITOL 15% | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

016269/004 | MANNITOL 20% | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

016269/005 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

016269/006 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

016472/002 | MANNITOL 10% | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

016472/004 | MANNITOL 20% | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

016472/005 | MANNITOL 15% | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

016704/002 | RESECTISOL | MANNITOL | SOLUTION/IRRIGATION | 5GM per 100ML |

016772/002 | RESECTISOL IN PLASTIC CONTAINER | MANNITOL | SOLUTION/IRRIGATION | 5GM per 100ML |

019603/001 | MANNITOL 5% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

019603/002 | MANNITOL 10% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

019603/003 | MANNITOL 15% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

019603/004 | MANNITOL 20% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

020006/001 | MANNITOL 5% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

020006/002 | MANNITOL 10% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

020006/003 | MANNITOL 15% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

020006/004 | MANNITOL 20% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

022368/001 | ARIDOL KIT | MANNITOL | POWDER/INHALATION | N per A,5MG,10MG,20MG,40MG |

022368/002 | ARIDOL | MANNITOL | POWDER/ INHALATION | 10MG |

022368/003 | ARIDOL | MANNITOL | POWDER/ INHALATION | 20MG |

022368/004 | ARIDOL | MANNITOL | POWDER/ INHALATION | 40MG |

080677/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

083051/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

086754/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

087409/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

087460/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

089239/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

089240/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

A licensed doctor will try to answer your question for free as quickly as possible. Free of charge during the beta period.

15% = 15gm / 100ml Convert the weight to Kg 150lb * (1Kg / 2.2lb) = 68.2Kg Setup (always include units!) (68.2Kg) * (1.5gm/1Kg) * (100ml/15gm) cancel out the Kg and gm, you are left with ml, the units you want Do the math (68,2 * 1.5 * 100) / (1 * 15) 10230 / 15 Answer = 682ml Email me if you have any questions or problems EDIT: Agreed, John. From a practical view that's how I would do it, but these instructors just see it as a math problem. Answered by Shaquana Montroy 1 year ago.

Sometimes, there's actually sense in things. In this case, the mannitol comes as 1.5 grams per 10 ml, so you only need round off the weight (70 kg is only four pounds off), multiply by ten, and give 700 ml. Answered by Darin Arriaga 1 year ago.

Mannitol Dose Answered by Isiah Vandehei 1 year ago.

Round off your patient's weight to 70 kg and it works itself out. By the way, you left out an important part: 1.5 grams per kg would be a very high dose (700 ml), and 1.5 ml/kg (15 grams) a conservative dose. Answered by Alexis Paulhus 1 year ago.

Ans: 7.5% Sodium Chloride Mannitol Salt Agar (MSA) is a selective (7.5 % soduim chloride) and differential (mannitol) medium. MSA is selective because it contains 7.5% NaCl (salt) which inhibits most organisms other than Staphylococci. Organisms that cannot tolerate high salt concentration will not grow on the plate. Most media contain about 0.5% NaCl. Therefore, MSA is said to be a selective medium for Staphylococci. MSA is differential beause it contains Mannitol. Mannitol fermentation is indicated by a change in the colour of the phenol red indicator which aids in the differentiation of Staphylococcal species. Mannitol fermenters produce acid and the colour of the medium around the colony changes to yellow while non-mannitol fermenters do not produce acid and the colour of the medium around the colony changes to red. Answered by Jasmine Thier 1 year ago.

This Site Might Help You. RE: What makes mannitol salt agar selective? Answered by Rikki Fleischman 1 year ago.

A selective medium only allows certain types of bacteria to grow on it, for example, just gram negatives can grow on some agars, and just Staph can grown on others. A differential medium is one which allows you to distinguish between bacteria which can grow on it. You should be able to find what those two agars are useful for... Answered by Evalyn Kirn 1 year ago.

agar agar.io Answered by Sherill Yngsdal 1 year ago.

Few organisms can use mannitol. Answered by Letisha Sjulstad 1 year ago.

Density of water = 1 gram per cm3 2% is 2 g per 100g of water or solution (unspecified in the question). However, it doesn't matter at all for the accuracy required. Let us assume that in each 100 g of solution there are 2 g of Mannitol, and that the density of the solution is 1 g per litre. Accurate enough for this dilute solution. We need 15 times more solution therefore we need 100X15 g of water = 1,500g of water giving 1.5 litres of water and 1.5 litres of solution to the accuracy required. Answered by Ollie Kallenberg 1 year ago.

What Is Mannitol Answered by Caroll Scherff 1 year ago.

Relax. He's given you a mild sugar and a mild diuretic. Nothing sinister there. Answered by Genny Oktavec 1 year ago.

the mass of 1 liter of your solution is 1.048*1000=1048g in this solution the mass of mannitol is 3.5*molar weight = 3.5*(6*12+14*1+6*16)=637g the number of moles of water is 1048-435=411g/18=22.83 so the relative fraction of water is x = 22.83/(22.83+3.5)=0.867 The vapor pressure is 0.867*55.5=48.13mmHg Answered by Rossana Rocquemore 1 year ago.

dude, you can't ask this question. It has to do with a lab that we weren't at......you either have to give more information or figure it out yourself. Answered by Almeda Coronado 1 year ago.

I can not understand these two problems at all: 1. In a 5.0% (m/v) glucose solution. How many L of a 5.0% (m/v) glucose solution would you need to obtain 55g of glucose? 2. A patient receives 100 ml of a 20% (m/v) mannitol solution every hour. How many grams of mannitol does the patient receive in 15 hours? 3. Also I solved a problem. But the units are NOT adding up. M is not the same thing as moles. I don't understand what I did exactly: What volume of 3.00 M KCL will contain 15.3 g of KCL? first I converted grams of KCL to moles. then I did 0.205 mol KCL divided by 3.00 M KCL. . I got liters and converted it to ml and got the right answer apparently. But how does mol and M cancel? I don't understand that. And when I do these problems how do I know when I cross multiply or if I divide because in that problem I divided. However in this problem I did not divide: How many grams of sodium chloride are needed to prepare 125 ml of 0.045 M NaCl solution? 0.045 M= x divided by 0.125 L. I multiplied 0.045 and 0.125 and got moles and converted it to grams and I got the right answer. But I cross multiplied, I didn't divide. Answered by Krissy Bulloch 1 year ago.

5% (m/v) means in 100 mL, 5 g is glucose. If you need 55 g of glucose, you need 55 g / 0.05 = 1100 mL or 1.1 L. You can also work it out from 100 mL contains 5 g of glucose. 55 g is 11x greater so you need 11 * 100 mL = 1100 mL = 1.1 L 2. 100 mL * 0.2 = 20 g of mannitol. Since the 100 mL is per hour, the 20 g of mannitol is per water. In 15 hours, they get 20 g mannitol/hr * 15 hours = 300 g 3. M is not moles. M is mole/L. If you have 10 moles of something disolved in 2 L, the concentration is 10 moles / 2 L = 5 mole/L = 5 M. < first I converted grams of KCL to moles > Correct. And 0.205 moles is correct. 0.205 mol KCL / 3.00 M KCL is the same as 0.205 mol KCl / 3.00 mole/L = 0.0684 L Why does mole / mole/L = L? mole / (mole/L). now, multiply top and bottom by L giving you mole * L / (mole/L * L). The moles cancel out and the two L terms in the bottom cancel out leaving you with L. < And when I do these problems how do I know when I cross multiply or if I divide because in that problem I divided > I'm not sure what you are asking. Watch your units and make sure they cancel out correctly, that will catch a lot of mistakes if you multiply when you should have divided. < How many grams of sodium chloride are needed to prepare 125 ml of 0.045 M NaCl solution? > So I have mL of NaCl solution and I have concentration in M which we know is mole/L. In this case we want to multiply because that will cancel out the volume terms, mL and L (with some conversion). 125 mL * 0.045 mole/L * 1 L / 1000 mL = 0.005625 mole of NaCl. The molar mass of NaCl is 58.44 g/mole so 0.005625 mole * 58.44 g/mole = 0.328 g NaCl. Notice how again the moles cancel out leaving you with grams, what you want when trying to find mass. If you don't include numbers, you just get 125 * 0.045 / 1000 and it's really easy to get confused 'should I multiply, should I divide?" and if you get it wrong, it's anything but obvious when you try to check your math. If you include your units, you have a built in check. An example 0.125 L / 0.2 mole/L = 0.625 L^2 / mole versus 0.125 L * 0.2 mole/L = 0.025 moles. If you are trying to find the moles of something, which set of units look correct? If you don't include units, you get 0.125 / 0.2 versus 0.125 * 0.2. Which one is right? How do you know? That's why you always include your units and make sure they cancel correctly. If they don't cancel correctly, you've likely made a mistake. Answered by Danita Bohnet 1 year ago.

15% = 15gm / 100ml Convert the weight to Kg 150lb * (1Kg / 2.2lb) = 68.2Kg Setup (always include units!) (68.2Kg) * (1.5gm/1Kg) * (100ml/15gm) cancel out the Kg and gm, you are left with ml, the units you want Do the math (68,2 * 1.5 * 100) / (1 * 15) 10230 / 15 Answer = 682ml Email me if you have any questions or problems EDIT: Agreed, John. From a practical view that's how I would do it, but these instructors just see it as a math problem. Answered by Millicent Sandman 1 year ago.

Sometimes, there's actually sense in things. In this case, the mannitol comes as 1.5 grams per 10 ml, so you only need round off the weight (70 kg is only four pounds off), multiply by ten, and give 700 ml. Answered by Fatimah Mehler 1 year ago.

Mannitol Dose Answered by Janella Grimme 1 year ago.

Round off your patient's weight to 70 kg and it works itself out. By the way, you left out an important part: 1.5 grams per kg would be a very high dose (700 ml), and 1.5 ml/kg (15 grams) a conservative dose. Answered by Palmer Jasmin 1 year ago.

Ans: 7.5% Sodium Chloride Mannitol Salt Agar (MSA) is a selective (7.5 % soduim chloride) and differential (mannitol) medium. MSA is selective because it contains 7.5% NaCl (salt) which inhibits most organisms other than Staphylococci. Organisms that cannot tolerate high salt concentration will not grow on the plate. Most media contain about 0.5% NaCl. Therefore, MSA is said to be a selective medium for Staphylococci. MSA is differential beause it contains Mannitol. Mannitol fermentation is indicated by a change in the colour of the phenol red indicator which aids in the differentiation of Staphylococcal species. Mannitol fermenters produce acid and the colour of the medium around the colony changes to yellow while non-mannitol fermenters do not produce acid and the colour of the medium around the colony changes to red. Answered by Aretha Mcquain 1 year ago.

This Site Might Help You. RE: What makes mannitol salt agar selective? Answered by Harry Packham 1 year ago.

A selective medium only allows certain types of bacteria to grow on it, for example, just gram negatives can grow on some agars, and just Staph can grown on others. A differential medium is one which allows you to distinguish between bacteria which can grow on it. You should be able to find what those two agars are useful for... Answered by Irma Balsam 1 year ago.

agar agar.io Answered by Linn Ramez 1 year ago.

Few organisms can use mannitol. Answered by Judi Howley 1 year ago.

Density of water = 1 gram per cm3 2% is 2 g per 100g of water or solution (unspecified in the question). However, it doesn't matter at all for the accuracy required. Let us assume that in each 100 g of solution there are 2 g of Mannitol, and that the density of the solution is 1 g per litre. Accurate enough for this dilute solution. We need 15 times more solution therefore we need 100X15 g of water = 1,500g of water giving 1.5 litres of water and 1.5 litres of solution to the accuracy required. Answered by Dianna Casuat 1 year ago.

What Is Mannitol Answered by Jay Longnecker 1 year ago.

Relax. He's given you a mild sugar and a mild diuretic. Nothing sinister there. Answered by Ray Koyama 1 year ago.

the mass of 1 liter of your solution is 1.048*1000=1048g in this solution the mass of mannitol is 3.5*molar weight = 3.5*(6*12+14*1+6*16)=637g the number of moles of water is 1048-435=411g/18=22.83 so the relative fraction of water is x = 22.83/(22.83+3.5)=0.867 The vapor pressure is 0.867*55.5=48.13mmHg Answered by Heriberto Dusen 1 year ago.

dude, you can't ask this question. It has to do with a lab that we weren't at......you either have to give more information or figure it out yourself. Answered by Naoma Forson 1 year ago.

I can not understand these two problems at all: 1. In a 5.0% (m/v) glucose solution. How many L of a 5.0% (m/v) glucose solution would you need to obtain 55g of glucose? 2. A patient receives 100 ml of a 20% (m/v) mannitol solution every hour. How many grams of mannitol does the patient receive in 15 hours? 3. Also I solved a problem. But the units are NOT adding up. M is not the same thing as moles. I don't understand what I did exactly: What volume of 3.00 M KCL will contain 15.3 g of KCL? first I converted grams of KCL to moles. then I did 0.205 mol KCL divided by 3.00 M KCL. . I got liters and converted it to ml and got the right answer apparently. But how does mol and M cancel? I don't understand that. And when I do these problems how do I know when I cross multiply or if I divide because in that problem I divided. However in this problem I did not divide: How many grams of sodium chloride are needed to prepare 125 ml of 0.045 M NaCl solution? 0.045 M= x divided by 0.125 L. I multiplied 0.045 and 0.125 and got moles and converted it to grams and I got the right answer. But I cross multiplied, I didn't divide. Answered by Annita Mirbaha 1 year ago.

5% (m/v) means in 100 mL, 5 g is glucose. If you need 55 g of glucose, you need 55 g / 0.05 = 1100 mL or 1.1 L. You can also work it out from 100 mL contains 5 g of glucose. 55 g is 11x greater so you need 11 * 100 mL = 1100 mL = 1.1 L 2. 100 mL * 0.2 = 20 g of mannitol. Since the 100 mL is per hour, the 20 g of mannitol is per water. In 15 hours, they get 20 g mannitol/hr * 15 hours = 300 g 3. M is not moles. M is mole/L. If you have 10 moles of something disolved in 2 L, the concentration is 10 moles / 2 L = 5 mole/L = 5 M. < first I converted grams of KCL to moles > Correct. And 0.205 moles is correct. 0.205 mol KCL / 3.00 M KCL is the same as 0.205 mol KCl / 3.00 mole/L = 0.0684 L Why does mole / mole/L = L? mole / (mole/L). now, multiply top and bottom by L giving you mole * L / (mole/L * L). The moles cancel out and the two L terms in the bottom cancel out leaving you with L. < And when I do these problems how do I know when I cross multiply or if I divide because in that problem I divided > I'm not sure what you are asking. Watch your units and make sure they cancel out correctly, that will catch a lot of mistakes if you multiply when you should have divided. < How many grams of sodium chloride are needed to prepare 125 ml of 0.045 M NaCl solution? > So I have mL of NaCl solution and I have concentration in M which we know is mole/L. In this case we want to multiply because that will cancel out the volume terms, mL and L (with some conversion). 125 mL * 0.045 mole/L * 1 L / 1000 mL = 0.005625 mole of NaCl. The molar mass of NaCl is 58.44 g/mole so 0.005625 mole * 58.44 g/mole = 0.328 g NaCl. Notice how again the moles cancel out leaving you with grams, what you want when trying to find mass. If you don't include numbers, you just get 125 * 0.045 / 1000 and it's really easy to get confused 'should I multiply, should I divide?" and if you get it wrong, it's anything but obvious when you try to check your math. If you include your units, you have a built in check. An example 0.125 L / 0.2 mole/L = 0.625 L^2 / mole versus 0.125 L * 0.2 mole/L = 0.025 moles. If you are trying to find the moles of something, which set of units look correct? If you don't include units, you get 0.125 / 0.2 versus 0.125 * 0.2. Which one is right? How do you know? That's why you always include your units and make sure they cancel correctly. If they don't cancel correctly, you've likely made a mistake. Answered by Harold Wenig 1 year ago.