ApplId/ProductId | Drug name | Active ingredient | Form | Strenght |
---|---|---|---|---|

014738/001 | MANNITOL 20% | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

016080/004 | MANNITOL 20% | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

016269/004 | MANNITOL 20% | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

016472/004 | MANNITOL 20% | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

ApplId/ProductId | Drug name | Active ingredient | Form | Strenght |
---|---|---|---|---|

005620/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

013684/001 | OSMITROL 5% IN WATER | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

013684/002 | OSMITROL 10% IN WATER | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

013684/003 | OSMITROL 20% IN WATER | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

013684/004 | OSMITROL 15% IN WATER | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

013684/005 | OSMITROL 5% IN WATER IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

013684/006 | OSMITROL 10% IN WATER IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

013684/007 | OSMITROL 20% IN WATER IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

013684/008 | OSMITROL 15% IN WATER IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

014738/001 | MANNITOL 20% | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

016080/001 | MANNITOL 5% | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

016080/002 | MANNITOL 10% | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

016080/003 | MANNITOL 15% | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

016080/004 | MANNITOL 20% | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

016080/005 | MANNITOL 15% W/ DEXTROSE 5% IN SODIUM CHLORIDE 0.45% | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

016080/006 | MANNITOL 10% W/ DEXTROSE 5% IN DISTILLED WATER | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

016080/007 | MANNITOL 5% W/ DEXTROSE 5% IN SODIUM CHLORIDE 0.12% | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

016269/001 | MANNITOL 5% | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

016269/002 | MANNITOL 10% | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

016269/003 | MANNITOL 15% | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

016269/004 | MANNITOL 20% | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

016269/005 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

016269/006 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

016472/002 | MANNITOL 10% | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

016472/004 | MANNITOL 20% | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

016472/005 | MANNITOL 15% | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

016704/002 | RESECTISOL | MANNITOL | SOLUTION/IRRIGATION | 5GM per 100ML |

016772/002 | RESECTISOL IN PLASTIC CONTAINER | MANNITOL | SOLUTION/IRRIGATION | 5GM per 100ML |

019603/001 | MANNITOL 5% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

019603/002 | MANNITOL 10% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

019603/003 | MANNITOL 15% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

019603/004 | MANNITOL 20% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

020006/001 | MANNITOL 5% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 5GM per 100ML |

020006/002 | MANNITOL 10% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 10GM per 100ML |

020006/003 | MANNITOL 15% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 15GM per 100ML |

020006/004 | MANNITOL 20% IN PLASTIC CONTAINER | MANNITOL | INJECTABLE/INJECTION | 20GM per 100ML |

022368/001 | ARIDOL KIT | MANNITOL | POWDER/INHALATION | N per A,5MG,10MG,20MG,40MG |

022368/002 | ARIDOL | MANNITOL | POWDER/ INHALATION | 10MG |

022368/003 | ARIDOL | MANNITOL | POWDER/ INHALATION | 20MG |

022368/004 | ARIDOL | MANNITOL | POWDER/ INHALATION | 40MG |

080677/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

083051/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

086754/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

087409/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

087460/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

089239/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

089240/001 | MANNITOL 25% | MANNITOL | INJECTABLE/INJECTION | 12.5GM per 50ML |

A licensed doctor will try to answer your question for free as quickly as possible. Free of charge during the beta period.

20% is 20gm / 100ml setup (20gm) / (100ml) = (100gm) / (xml) solve for x ((100ml) * (100gm)) / 20gm = x 500ml = x If you have any questions or problems, email me. Answered by Trisha Wertenberger 2 years ago.

your medical school or nursing school homework: I dont want to do it for you. Answered by Mildred Hellweg 2 years ago.

100. mL of a 20.% (m/v) mannitol solution has 20. grams of mannitol in 100. ml of solution so 1.How many grams of mannitol are given in 1 hour?.... 20. grams 2.How many grams of mannitol does the patient receive in 24 hours... 480 grams Answered by Leatrice Petrizzo 2 years ago.

There is not any information provided on how many grams of mannitol would be in one milliliter. Answered by Jospeh Delea 2 years ago.

20 Mannitol Answered by Rick Kennin 2 years ago.

daddyrx is correct. In medicine, when you see these things labelled as a percent, it isn't the proportional percentage that you're used to thinking about, but a shorthand for "grams per deciliter." 20 grams per 100 ml is 100 grams in 500 ml. Answered by Lindsay Buescher 2 years ago.

20% means 20gm/100ml set up a ratio: (20gm/100ml) = (100gm/xml) 100ml * 100gm = 20gm * xml xml = (100ml * 100gm) / 20gm xml = 500ml Answered by Jaclyn Schweder 2 years ago.

forgive me, but you question makes no sense to me. please reword and rephrase or redo, using complete sentences and common english language structure. thanks. Answered by Lore Stephan 2 years ago.

Percentages are grams/100ml So, 20% solution= 20grams/100mls 100gm/ X mls = 20 grams/100 mls solving for X mls yields: (100 gm)100mls/20grams = X mls X mls = 500 mls Answered by Shan Oxman 2 years ago.

You gotta work this out yourself!! 20% = 20g in 100ml so 100gm is 5 times this.. It's not rocket science. Answered by Rebecca Cambric 2 years ago.

You will not succeed if you do not do your own homework. Answered by Dallas Umscheid 2 years ago.

I can not understand these two problems at all: 1. In a 5.0% (m/v) glucose solution. How many L of a 5.0% (m/v) glucose solution would you need to obtain 55g of glucose? 2. A patient receives 100 ml of a 20% (m/v) mannitol solution every hour. How many grams of mannitol does the patient receive in 15 hours? 3. Also I solved a problem. But the units are NOT adding up. M is not the same thing as moles. I don't understand what I did exactly: What volume of 3.00 M KCL will contain 15.3 g of KCL? first I converted grams of KCL to moles. then I did 0.205 mol KCL divided by 3.00 M KCL. . I got liters and converted it to ml and got the right answer apparently. But how does mol and M cancel? I don't understand that. And when I do these problems how do I know when I cross multiply or if I divide because in that problem I divided. However in this problem I did not divide: How many grams of sodium chloride are needed to prepare 125 ml of 0.045 M NaCl solution? 0.045 M= x divided by 0.125 L. I multiplied 0.045 and 0.125 and got moles and converted it to grams and I got the right answer. But I cross multiplied, I didn't divide. Answered by Aliza Toussand 2 years ago.

5% (m/v) means in 100 mL, 5 g is glucose. If you need 55 g of glucose, you need 55 g / 0.05 = 1100 mL or 1.1 L. You can also work it out from 100 mL contains 5 g of glucose. 55 g is 11x greater so you need 11 * 100 mL = 1100 mL = 1.1 L 2. 100 mL * 0.2 = 20 g of mannitol. Since the 100 mL is per hour, the 20 g of mannitol is per water. In 15 hours, they get 20 g mannitol/hr * 15 hours = 300 g 3. M is not moles. M is mole/L. If you have 10 moles of something disolved in 2 L, the concentration is 10 moles / 2 L = 5 mole/L = 5 M. < first I converted grams of KCL to moles > Correct. And 0.205 moles is correct. 0.205 mol KCL / 3.00 M KCL is the same as 0.205 mol KCl / 3.00 mole/L = 0.0684 L Why does mole / mole/L = L? mole / (mole/L). now, multiply top and bottom by L giving you mole * L / (mole/L * L). The moles cancel out and the two L terms in the bottom cancel out leaving you with L. < And when I do these problems how do I know when I cross multiply or if I divide because in that problem I divided > I'm not sure what you are asking. Watch your units and make sure they cancel out correctly, that will catch a lot of mistakes if you multiply when you should have divided. < How many grams of sodium chloride are needed to prepare 125 ml of 0.045 M NaCl solution? > So I have mL of NaCl solution and I have concentration in M which we know is mole/L. In this case we want to multiply because that will cancel out the volume terms, mL and L (with some conversion). 125 mL * 0.045 mole/L * 1 L / 1000 mL = 0.005625 mole of NaCl. The molar mass of NaCl is 58.44 g/mole so 0.005625 mole * 58.44 g/mole = 0.328 g NaCl. Notice how again the moles cancel out leaving you with grams, what you want when trying to find mass. If you don't include numbers, you just get 125 * 0.045 / 1000 and it's really easy to get confused 'should I multiply, should I divide?" and if you get it wrong, it's anything but obvious when you try to check your math. If you include your units, you have a built in check. An example 0.125 L / 0.2 mole/L = 0.625 L^2 / mole versus 0.125 L * 0.2 mole/L = 0.025 moles. If you are trying to find the moles of something, which set of units look correct? If you don't include units, you get 0.125 / 0.2 versus 0.125 * 0.2. Which one is right? How do you know? That's why you always include your units and make sure they cancel correctly. If they don't cancel correctly, you've likely made a mistake. Answered by Dominique Lacharite 2 years ago.

What Is Mannitol Answered by Gita Baronne 2 years ago.

If given stock solutions of 1M D-mannitol, 250mM cetyl alcohol, and 1μM sodium acetate. How much of each solution would be needed to prepare 500mL of a reagent that contains 0.2M D-mannitol, 20mM cetyl alcohol, and 0.1 μM sodium acetate. M=molar mM=millimolar μM=microMolar I have no idea PLEASE HELP and if you can show how to do it thats awesome....I'm Sure its hard but I really appreciate it Answered by Kareen Orem 2 years ago.

For each substance, use the relationship M1V1 = M2V2 Mannitol 500 mL (0.2 M) = V2(1 M) V2 = 100 mL Cetyl alcohol 500 mL X 20 mM = V2 ( 250 mM) V2 = 40 mL Sodium acetate 500 mL (0.1 uM) = V2 ( 1 uM) V2 = 50 mL So, you will combine 100 mL of the original mannitol stock, 40 mL of the cetyl alcohol stock and 50 mL of the sodium acetate stock, and add water until the total volume of the solution is 500 mL. Answered by Nicky Stolarski 2 years ago.

using fact many components/compounds are soluble whilst dissolved in H20, meaning that as quickly as blended with H2O, the compounds dissociate one hundred% and ruin aside into thier unmarried aspects as loose ions. those loose ions, cations (+ can charge) and anions(- can charge), are left to react with different ions/compounds of opposite quotes. to that end, using fact that many components/compounds are soluble in water (i.e. all compunds containing alkali metallic ions, nitrates, bicarbonates, cholrates), many chemical reactions ensue in those aqueous recommendations. Answered by Jacob Jaminet 2 years ago.

I cannot figure these out, can anyone help? 1. If an injectable contains 20% of mannitol, how many mls of the injection should be administered to provide 100gm of mannitol? 2.If 500 gm of dextrose are dissolved in 600ml of water, with the final volume being 1000ml, what is the percentage strength of the dextrose in the solution? 3. You have a 70% dextrose solution. How many grams of dextrose are in 400ml? If anyone could help with any of these that would be GREAT! Answered by Saran Pittmon 2 years ago.

% solution = gm/100mL all of these can be solved by cross multiplying 1. 20% = 20gm/100mL; if you cross multiply, you get 500mL (or 100/0.2 = 500mL) 2. 500gm/1000mL x 100mL = 50% 3. 70gm/100mL x 400mL = 280gm Answered by Enid Hoppa 2 years ago.

1. Depend on how much (gms) of mannitol present in the solution. 2. 50% (water is quantity sufficient) 3. 280 gm Answered by Leigh Lucksom 2 years ago.

20% is 20gm / 100ml setup (20gm) / (100ml) = (100gm) / (xml) solve for x ((100ml) * (100gm)) / 20gm = x 500ml = x If you have any questions or problems, email me. Answered by Roselle Hagelgans 2 years ago.

your medical school or nursing school homework: I dont want to do it for you. Answered by Keith Hanegan 2 years ago.

100. mL of a 20.% (m/v) mannitol solution has 20. grams of mannitol in 100. ml of solution so 1.How many grams of mannitol are given in 1 hour?.... 20. grams 2.How many grams of mannitol does the patient receive in 24 hours... 480 grams Answered by Javier Jenks 2 years ago.

There is not any information provided on how many grams of mannitol would be in one milliliter. Answered by Laverna Lot 2 years ago.

20 Mannitol Answered by Kiera Corbeil 2 years ago.

daddyrx is correct. In medicine, when you see these things labelled as a percent, it isn't the proportional percentage that you're used to thinking about, but a shorthand for "grams per deciliter." 20 grams per 100 ml is 100 grams in 500 ml. Answered by Young Stuckert 2 years ago.

20% means 20gm/100ml set up a ratio: (20gm/100ml) = (100gm/xml) 100ml * 100gm = 20gm * xml xml = (100ml * 100gm) / 20gm xml = 500ml Answered by Zula Har 2 years ago.

forgive me, but you question makes no sense to me. please reword and rephrase or redo, using complete sentences and common english language structure. thanks. Answered by Tresa Dou 2 years ago.

Percentages are grams/100ml So, 20% solution= 20grams/100mls 100gm/ X mls = 20 grams/100 mls solving for X mls yields: (100 gm)100mls/20grams = X mls X mls = 500 mls Answered by Barney Gorovitz 2 years ago.

You gotta work this out yourself!! 20% = 20g in 100ml so 100gm is 5 times this.. It's not rocket science. Answered by Dalene Teti 2 years ago.

You will not succeed if you do not do your own homework. Answered by Etsuko Hoffee 2 years ago.

I can not understand these two problems at all: 1. In a 5.0% (m/v) glucose solution. How many L of a 5.0% (m/v) glucose solution would you need to obtain 55g of glucose? 2. A patient receives 100 ml of a 20% (m/v) mannitol solution every hour. How many grams of mannitol does the patient receive in 15 hours? 3. Also I solved a problem. But the units are NOT adding up. M is not the same thing as moles. I don't understand what I did exactly: What volume of 3.00 M KCL will contain 15.3 g of KCL? first I converted grams of KCL to moles. then I did 0.205 mol KCL divided by 3.00 M KCL. . I got liters and converted it to ml and got the right answer apparently. But how does mol and M cancel? I don't understand that. And when I do these problems how do I know when I cross multiply or if I divide because in that problem I divided. However in this problem I did not divide: How many grams of sodium chloride are needed to prepare 125 ml of 0.045 M NaCl solution? 0.045 M= x divided by 0.125 L. I multiplied 0.045 and 0.125 and got moles and converted it to grams and I got the right answer. But I cross multiplied, I didn't divide. Answered by Kenyatta Hessling 2 years ago.

5% (m/v) means in 100 mL, 5 g is glucose. If you need 55 g of glucose, you need 55 g / 0.05 = 1100 mL or 1.1 L. You can also work it out from 100 mL contains 5 g of glucose. 55 g is 11x greater so you need 11 * 100 mL = 1100 mL = 1.1 L 2. 100 mL * 0.2 = 20 g of mannitol. Since the 100 mL is per hour, the 20 g of mannitol is per water. In 15 hours, they get 20 g mannitol/hr * 15 hours = 300 g 3. M is not moles. M is mole/L. If you have 10 moles of something disolved in 2 L, the concentration is 10 moles / 2 L = 5 mole/L = 5 M. < first I converted grams of KCL to moles > Correct. And 0.205 moles is correct. 0.205 mol KCL / 3.00 M KCL is the same as 0.205 mol KCl / 3.00 mole/L = 0.0684 L Why does mole / mole/L = L? mole / (mole/L). now, multiply top and bottom by L giving you mole * L / (mole/L * L). The moles cancel out and the two L terms in the bottom cancel out leaving you with L. < And when I do these problems how do I know when I cross multiply or if I divide because in that problem I divided > I'm not sure what you are asking. Watch your units and make sure they cancel out correctly, that will catch a lot of mistakes if you multiply when you should have divided. < How many grams of sodium chloride are needed to prepare 125 ml of 0.045 M NaCl solution? > So I have mL of NaCl solution and I have concentration in M which we know is mole/L. In this case we want to multiply because that will cancel out the volume terms, mL and L (with some conversion). 125 mL * 0.045 mole/L * 1 L / 1000 mL = 0.005625 mole of NaCl. The molar mass of NaCl is 58.44 g/mole so 0.005625 mole * 58.44 g/mole = 0.328 g NaCl. Notice how again the moles cancel out leaving you with grams, what you want when trying to find mass. If you don't include numbers, you just get 125 * 0.045 / 1000 and it's really easy to get confused 'should I multiply, should I divide?" and if you get it wrong, it's anything but obvious when you try to check your math. If you include your units, you have a built in check. An example 0.125 L / 0.2 mole/L = 0.625 L^2 / mole versus 0.125 L * 0.2 mole/L = 0.025 moles. If you are trying to find the moles of something, which set of units look correct? If you don't include units, you get 0.125 / 0.2 versus 0.125 * 0.2. Which one is right? How do you know? That's why you always include your units and make sure they cancel correctly. If they don't cancel correctly, you've likely made a mistake. Answered by Desiree Gildea 2 years ago.

What Is Mannitol Answered by Paola Cockerhan 2 years ago.

If given stock solutions of 1M D-mannitol, 250mM cetyl alcohol, and 1μM sodium acetate. How much of each solution would be needed to prepare 500mL of a reagent that contains 0.2M D-mannitol, 20mM cetyl alcohol, and 0.1 μM sodium acetate. M=molar mM=millimolar μM=microMolar I have no idea PLEASE HELP and if you can show how to do it thats awesome....I'm Sure its hard but I really appreciate it Answered by Weston Katnik 2 years ago.

For each substance, use the relationship M1V1 = M2V2 Mannitol 500 mL (0.2 M) = V2(1 M) V2 = 100 mL Cetyl alcohol 500 mL X 20 mM = V2 ( 250 mM) V2 = 40 mL Sodium acetate 500 mL (0.1 uM) = V2 ( 1 uM) V2 = 50 mL So, you will combine 100 mL of the original mannitol stock, 40 mL of the cetyl alcohol stock and 50 mL of the sodium acetate stock, and add water until the total volume of the solution is 500 mL. Answered by Hans Robledo 2 years ago.

using fact many components/compounds are soluble whilst dissolved in H20, meaning that as quickly as blended with H2O, the compounds dissociate one hundred% and ruin aside into thier unmarried aspects as loose ions. those loose ions, cations (+ can charge) and anions(- can charge), are left to react with different ions/compounds of opposite quotes. to that end, using fact that many components/compounds are soluble in water (i.e. all compunds containing alkali metallic ions, nitrates, bicarbonates, cholrates), many chemical reactions ensue in those aqueous recommendations. Answered by Twanna Tagupa 2 years ago.

I cannot figure these out, can anyone help? 1. If an injectable contains 20% of mannitol, how many mls of the injection should be administered to provide 100gm of mannitol? 2.If 500 gm of dextrose are dissolved in 600ml of water, with the final volume being 1000ml, what is the percentage strength of the dextrose in the solution? 3. You have a 70% dextrose solution. How many grams of dextrose are in 400ml? If anyone could help with any of these that would be GREAT! Answered by Crystle Moynihan 2 years ago.

% solution = gm/100mL all of these can be solved by cross multiplying 1. 20% = 20gm/100mL; if you cross multiply, you get 500mL (or 100/0.2 = 500mL) 2. 500gm/1000mL x 100mL = 50% 3. 70gm/100mL x 400mL = 280gm Answered by Donita Ameling 2 years ago.

1. Depend on how much (gms) of mannitol present in the solution. 2. 50% (water is quantity sufficient) 3. 280 gm Answered by Georgianne Varanda 2 years ago.

20% is 20gm / 100ml setup (20gm) / (100ml) = (100gm) / (xml) solve for x ((100ml) * (100gm)) / 20gm = x 500ml = x If you have any questions or problems, email me. Answered by Nelida Pedigo 2 years ago.

your medical school or nursing school homework: I dont want to do it for you. Answered by Pinkie Tiede 2 years ago.

100. mL of a 20.% (m/v) mannitol solution has 20. grams of mannitol in 100. ml of solution so 1.How many grams of mannitol are given in 1 hour?.... 20. grams 2.How many grams of mannitol does the patient receive in 24 hours... 480 grams Answered by Augustus Chern 2 years ago.

There is not any information provided on how many grams of mannitol would be in one milliliter. Answered by Cecil Spalter 2 years ago.

20 Mannitol Answered by Ramonita Fishbein 2 years ago.

daddyrx is correct. In medicine, when you see these things labelled as a percent, it isn't the proportional percentage that you're used to thinking about, but a shorthand for "grams per deciliter." 20 grams per 100 ml is 100 grams in 500 ml. Answered by Darci Silleman 2 years ago.

20% means 20gm/100ml set up a ratio: (20gm/100ml) = (100gm/xml) 100ml * 100gm = 20gm * xml xml = (100ml * 100gm) / 20gm xml = 500ml Answered by Dann Cathell 2 years ago.

forgive me, but you question makes no sense to me. please reword and rephrase or redo, using complete sentences and common english language structure. thanks. Answered by Ileana Soffer 2 years ago.

Percentages are grams/100ml So, 20% solution= 20grams/100mls 100gm/ X mls = 20 grams/100 mls solving for X mls yields: (100 gm)100mls/20grams = X mls X mls = 500 mls Answered by Kala Dundee 2 years ago.

You gotta work this out yourself!! 20% = 20g in 100ml so 100gm is 5 times this.. It's not rocket science. Answered by Elvera Hereford 2 years ago.

You will not succeed if you do not do your own homework. Answered by Doug Chillemi 2 years ago.

I can not understand these two problems at all: 1. In a 5.0% (m/v) glucose solution. How many L of a 5.0% (m/v) glucose solution would you need to obtain 55g of glucose? 2. A patient receives 100 ml of a 20% (m/v) mannitol solution every hour. How many grams of mannitol does the patient receive in 15 hours? 3. Also I solved a problem. But the units are NOT adding up. M is not the same thing as moles. I don't understand what I did exactly: What volume of 3.00 M KCL will contain 15.3 g of KCL? first I converted grams of KCL to moles. then I did 0.205 mol KCL divided by 3.00 M KCL. . I got liters and converted it to ml and got the right answer apparently. But how does mol and M cancel? I don't understand that. And when I do these problems how do I know when I cross multiply or if I divide because in that problem I divided. However in this problem I did not divide: How many grams of sodium chloride are needed to prepare 125 ml of 0.045 M NaCl solution? 0.045 M= x divided by 0.125 L. I multiplied 0.045 and 0.125 and got moles and converted it to grams and I got the right answer. But I cross multiplied, I didn't divide. Answered by Kay Mazzarella 2 years ago.

5% (m/v) means in 100 mL, 5 g is glucose. If you need 55 g of glucose, you need 55 g / 0.05 = 1100 mL or 1.1 L. You can also work it out from 100 mL contains 5 g of glucose. 55 g is 11x greater so you need 11 * 100 mL = 1100 mL = 1.1 L 2. 100 mL * 0.2 = 20 g of mannitol. Since the 100 mL is per hour, the 20 g of mannitol is per water. In 15 hours, they get 20 g mannitol/hr * 15 hours = 300 g 3. M is not moles. M is mole/L. If you have 10 moles of something disolved in 2 L, the concentration is 10 moles / 2 L = 5 mole/L = 5 M. < first I converted grams of KCL to moles > Correct. And 0.205 moles is correct. 0.205 mol KCL / 3.00 M KCL is the same as 0.205 mol KCl / 3.00 mole/L = 0.0684 L Why does mole / mole/L = L? mole / (mole/L). now, multiply top and bottom by L giving you mole * L / (mole/L * L). The moles cancel out and the two L terms in the bottom cancel out leaving you with L. < And when I do these problems how do I know when I cross multiply or if I divide because in that problem I divided > I'm not sure what you are asking. Watch your units and make sure they cancel out correctly, that will catch a lot of mistakes if you multiply when you should have divided. < How many grams of sodium chloride are needed to prepare 125 ml of 0.045 M NaCl solution? > So I have mL of NaCl solution and I have concentration in M which we know is mole/L. In this case we want to multiply because that will cancel out the volume terms, mL and L (with some conversion). 125 mL * 0.045 mole/L * 1 L / 1000 mL = 0.005625 mole of NaCl. The molar mass of NaCl is 58.44 g/mole so 0.005625 mole * 58.44 g/mole = 0.328 g NaCl. Notice how again the moles cancel out leaving you with grams, what you want when trying to find mass. If you don't include numbers, you just get 125 * 0.045 / 1000 and it's really easy to get confused 'should I multiply, should I divide?" and if you get it wrong, it's anything but obvious when you try to check your math. If you include your units, you have a built in check. An example 0.125 L / 0.2 mole/L = 0.625 L^2 / mole versus 0.125 L * 0.2 mole/L = 0.025 moles. If you are trying to find the moles of something, which set of units look correct? If you don't include units, you get 0.125 / 0.2 versus 0.125 * 0.2. Which one is right? How do you know? That's why you always include your units and make sure they cancel correctly. If they don't cancel correctly, you've likely made a mistake. Answered by Autumn Wiebusch 2 years ago.

What Is Mannitol Answered by Tobie Geddings 2 years ago.

If given stock solutions of 1M D-mannitol, 250mM cetyl alcohol, and 1μM sodium acetate. How much of each solution would be needed to prepare 500mL of a reagent that contains 0.2M D-mannitol, 20mM cetyl alcohol, and 0.1 μM sodium acetate. M=molar mM=millimolar μM=microMolar I have no idea PLEASE HELP and if you can show how to do it thats awesome....I'm Sure its hard but I really appreciate it Answered by Roxann Bochek 2 years ago.

For each substance, use the relationship M1V1 = M2V2 Mannitol 500 mL (0.2 M) = V2(1 M) V2 = 100 mL Cetyl alcohol 500 mL X 20 mM = V2 ( 250 mM) V2 = 40 mL Sodium acetate 500 mL (0.1 uM) = V2 ( 1 uM) V2 = 50 mL So, you will combine 100 mL of the original mannitol stock, 40 mL of the cetyl alcohol stock and 50 mL of the sodium acetate stock, and add water until the total volume of the solution is 500 mL. Answered by Lorita Gorgone 2 years ago.

using fact many components/compounds are soluble whilst dissolved in H20, meaning that as quickly as blended with H2O, the compounds dissociate one hundred% and ruin aside into thier unmarried aspects as loose ions. those loose ions, cations (+ can charge) and anions(- can charge), are left to react with different ions/compounds of opposite quotes. to that end, using fact that many components/compounds are soluble in water (i.e. all compunds containing alkali metallic ions, nitrates, bicarbonates, cholrates), many chemical reactions ensue in those aqueous recommendations. Answered by Maya Learman 2 years ago.

I cannot figure these out, can anyone help? 1. If an injectable contains 20% of mannitol, how many mls of the injection should be administered to provide 100gm of mannitol? 2.If 500 gm of dextrose are dissolved in 600ml of water, with the final volume being 1000ml, what is the percentage strength of the dextrose in the solution? 3. You have a 70% dextrose solution. How many grams of dextrose are in 400ml? If anyone could help with any of these that would be GREAT! Answered by Lucio Bjorkman 2 years ago.

% solution = gm/100mL all of these can be solved by cross multiplying 1. 20% = 20gm/100mL; if you cross multiply, you get 500mL (or 100/0.2 = 500mL) 2. 500gm/1000mL x 100mL = 50% 3. 70gm/100mL x 400mL = 280gm Answered by Kanesha Bodon 2 years ago.

1. Depend on how much (gms) of mannitol present in the solution. 2. 50% (water is quantity sufficient) 3. 280 gm Answered by Terra Posthumus 2 years ago.

20% is 20gm / 100ml setup (20gm) / (100ml) = (100gm) / (xml) solve for x ((100ml) * (100gm)) / 20gm = x 500ml = x If you have any questions or problems, email me. Answered by Yukiko Hollaway 2 years ago.

your medical school or nursing school homework: I dont want to do it for you. Answered by Dion Leibold 2 years ago.

100. mL of a 20.% (m/v) mannitol solution has 20. grams of mannitol in 100. ml of solution so 1.How many grams of mannitol are given in 1 hour?.... 20. grams 2.How many grams of mannitol does the patient receive in 24 hours... 480 grams Answered by Randi Vaneps 2 years ago.

There is not any information provided on how many grams of mannitol would be in one milliliter. Answered by Lurlene Kriete 2 years ago.

20 Mannitol Answered by Lynn Heverley 2 years ago.

daddyrx is correct. In medicine, when you see these things labelled as a percent, it isn't the proportional percentage that you're used to thinking about, but a shorthand for "grams per deciliter." 20 grams per 100 ml is 100 grams in 500 ml. Answered by Lynnette Hairell 2 years ago.

20% means 20gm/100ml set up a ratio: (20gm/100ml) = (100gm/xml) 100ml * 100gm = 20gm * xml xml = (100ml * 100gm) / 20gm xml = 500ml Answered by Glady Prudom 2 years ago.

forgive me, but you question makes no sense to me. please reword and rephrase or redo, using complete sentences and common english language structure. thanks. Answered by Shaunta Liverance 2 years ago.

Percentages are grams/100ml So, 20% solution= 20grams/100mls 100gm/ X mls = 20 grams/100 mls solving for X mls yields: (100 gm)100mls/20grams = X mls X mls = 500 mls Answered by Jamel Oberholtzer 2 years ago.

You gotta work this out yourself!! 20% = 20g in 100ml so 100gm is 5 times this.. It's not rocket science. Answered by Deneen Egure 2 years ago.

You will not succeed if you do not do your own homework. Answered by Leda Strauss 2 years ago.

I can not understand these two problems at all: 1. In a 5.0% (m/v) glucose solution. How many L of a 5.0% (m/v) glucose solution would you need to obtain 55g of glucose? 2. A patient receives 100 ml of a 20% (m/v) mannitol solution every hour. How many grams of mannitol does the patient receive in 15 hours? 3. Also I solved a problem. But the units are NOT adding up. M is not the same thing as moles. I don't understand what I did exactly: What volume of 3.00 M KCL will contain 15.3 g of KCL? first I converted grams of KCL to moles. then I did 0.205 mol KCL divided by 3.00 M KCL. . I got liters and converted it to ml and got the right answer apparently. But how does mol and M cancel? I don't understand that. And when I do these problems how do I know when I cross multiply or if I divide because in that problem I divided. However in this problem I did not divide: How many grams of sodium chloride are needed to prepare 125 ml of 0.045 M NaCl solution? 0.045 M= x divided by 0.125 L. I multiplied 0.045 and 0.125 and got moles and converted it to grams and I got the right answer. But I cross multiplied, I didn't divide. Answered by Donetta Sjoberg 2 years ago.

5% (m/v) means in 100 mL, 5 g is glucose. If you need 55 g of glucose, you need 55 g / 0.05 = 1100 mL or 1.1 L. You can also work it out from 100 mL contains 5 g of glucose. 55 g is 11x greater so you need 11 * 100 mL = 1100 mL = 1.1 L 2. 100 mL * 0.2 = 20 g of mannitol. Since the 100 mL is per hour, the 20 g of mannitol is per water. In 15 hours, they get 20 g mannitol/hr * 15 hours = 300 g 3. M is not moles. M is mole/L. If you have 10 moles of something disolved in 2 L, the concentration is 10 moles / 2 L = 5 mole/L = 5 M. < first I converted grams of KCL to moles > Correct. And 0.205 moles is correct. 0.205 mol KCL / 3.00 M KCL is the same as 0.205 mol KCl / 3.00 mole/L = 0.0684 L Why does mole / mole/L = L? mole / (mole/L). now, multiply top and bottom by L giving you mole * L / (mole/L * L). The moles cancel out and the two L terms in the bottom cancel out leaving you with L. < And when I do these problems how do I know when I cross multiply or if I divide because in that problem I divided > I'm not sure what you are asking. Watch your units and make sure they cancel out correctly, that will catch a lot of mistakes if you multiply when you should have divided. < How many grams of sodium chloride are needed to prepare 125 ml of 0.045 M NaCl solution? > So I have mL of NaCl solution and I have concentration in M which we know is mole/L. In this case we want to multiply because that will cancel out the volume terms, mL and L (with some conversion). 125 mL * 0.045 mole/L * 1 L / 1000 mL = 0.005625 mole of NaCl. The molar mass of NaCl is 58.44 g/mole so 0.005625 mole * 58.44 g/mole = 0.328 g NaCl. Notice how again the moles cancel out leaving you with grams, what you want when trying to find mass. If you don't include numbers, you just get 125 * 0.045 / 1000 and it's really easy to get confused 'should I multiply, should I divide?" and if you get it wrong, it's anything but obvious when you try to check your math. If you include your units, you have a built in check. An example 0.125 L / 0.2 mole/L = 0.625 L^2 / mole versus 0.125 L * 0.2 mole/L = 0.025 moles. If you are trying to find the moles of something, which set of units look correct? If you don't include units, you get 0.125 / 0.2 versus 0.125 * 0.2. Which one is right? How do you know? That's why you always include your units and make sure they cancel correctly. If they don't cancel correctly, you've likely made a mistake. Answered by Xiomara Pathak 2 years ago.

What Is Mannitol Answered by Alise Deeb 2 years ago.

If given stock solutions of 1M D-mannitol, 250mM cetyl alcohol, and 1μM sodium acetate. How much of each solution would be needed to prepare 500mL of a reagent that contains 0.2M D-mannitol, 20mM cetyl alcohol, and 0.1 μM sodium acetate. M=molar mM=millimolar μM=microMolar I have no idea PLEASE HELP and if you can show how to do it thats awesome....I'm Sure its hard but I really appreciate it Answered by Janita Stclaire 2 years ago.

For each substance, use the relationship M1V1 = M2V2 Mannitol 500 mL (0.2 M) = V2(1 M) V2 = 100 mL Cetyl alcohol 500 mL X 20 mM = V2 ( 250 mM) V2 = 40 mL Sodium acetate 500 mL (0.1 uM) = V2 ( 1 uM) V2 = 50 mL So, you will combine 100 mL of the original mannitol stock, 40 mL of the cetyl alcohol stock and 50 mL of the sodium acetate stock, and add water until the total volume of the solution is 500 mL. Answered by Laura Horseford 2 years ago.

using fact many components/compounds are soluble whilst dissolved in H20, meaning that as quickly as blended with H2O, the compounds dissociate one hundred% and ruin aside into thier unmarried aspects as loose ions. those loose ions, cations (+ can charge) and anions(- can charge), are left to react with different ions/compounds of opposite quotes. to that end, using fact that many components/compounds are soluble in water (i.e. all compunds containing alkali metallic ions, nitrates, bicarbonates, cholrates), many chemical reactions ensue in those aqueous recommendations. Answered by Arianne Gavidia 2 years ago.

I cannot figure these out, can anyone help? 1. If an injectable contains 20% of mannitol, how many mls of the injection should be administered to provide 100gm of mannitol? 2.If 500 gm of dextrose are dissolved in 600ml of water, with the final volume being 1000ml, what is the percentage strength of the dextrose in the solution? 3. You have a 70% dextrose solution. How many grams of dextrose are in 400ml? If anyone could help with any of these that would be GREAT! Answered by Lanora Majeske 2 years ago.

% solution = gm/100mL all of these can be solved by cross multiplying 1. 20% = 20gm/100mL; if you cross multiply, you get 500mL (or 100/0.2 = 500mL) 2. 500gm/1000mL x 100mL = 50% 3. 70gm/100mL x 400mL = 280gm Answered by Maurine Slattery 2 years ago.

1. Depend on how much (gms) of mannitol present in the solution. 2. 50% (water is quantity sufficient) 3. 280 gm Answered by Eulah Sgueglia 2 years ago.